A100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball that is moving to the left at 3.0 m/s.

if the collision is perfectly elastic, what are the speeds of each ball after the collision?

The final speed of the 100-g ball is about 5.3 m/s to the left

The final speed of the 200-g ball is about 1.7 m/s to the right

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

mass of ball 1 = m₁ = 100 g

initial velocity of ball 1 = u₁ = 4.0 m/s

mass of ball 2 = m₂ = 200 g

initial velocity of ball 2 = u₂ = -3.0 m/s

Asked:

final velocity of ball 1 = v₁ = ?

final velocity of ball 2 = v₂ = ?

Solution:

Firstly , we will use Conservation of Momentum Law as follows:

→ Equation 1

If the collision is perfectly elastic , then:

→ Equation 2

Let's solve the two Equations above:

(Equation 1) + (Equation 2) ↓

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

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