An object is launched at 20 m/s from a height of 65 m. the equation for the height (h) in terms of time (t) is given by h(t) = -4.9t² + 20t + 65. what is the object's maximum height? the numeric answer only, rounded to the nearest meter.

Maximum height will be 85 meter

Explanation:

given that height of an object is function of time and it is given as

here we can write it as

now we can compare it with the kinematics equation

now if we compare the two equations then we will have

initial height of object = 65 m

initial velocity of projection = 20 m/s

acceleration = - 9.8 m/s/s

now for the maximum height at which its final speed will become zero is given as

So maximum height in meter in nearest integer will be 85 m

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