5 While traveling on a curved dusty road, a car gets a centripetal acceleration of 12.5 m/s2. If the radius is 1200 m, what is the tangential velocity of the car? 6. Find the mass of a circular moving object that has a centripetal force of 1345 N and an accel-eration of 36.2 m/s2.

7. Ruichao is spinning her backpack around and around. If her backpack has a mass of 8 kg, what centripetal acceleration would it have if she applies a centripetal force of 120 N?

8. Callum is playing tetherball. The tetherball has a mass of 0.4 kg and has a tangential velocity of 2.4 m/s. If the tetherball rope is 1.5 m long, what centripetal force does Callum’s tetherball have?

9. Melissa and Cody are on a fun fair ride that spins them in a circle with radius 6 meters. If Melissa has a mass of 55 kg and Cody has a mass of 65 kg, what centripetal force will they have together if they have an acceleration of 2.2 m/s2?

10. Bethany is swinging her grocery bag as she walks. The radius of her swing is 0.8 m. If she can provide a tangential velocity of 2.7 m/s and a centripetal force of 68 N, what centripetal accel-eration will her groceries have?

(I'm sorry I need help with those problems)

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

talk back to him about the sport and show him your expertise or leave the room

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

there are no contact forces mentioned on the list of choices that you've provided.