6. Fig. 3.1 shows a pond that is kept at a conslant depth by a pressure-operated valve in the base.
water
pressure oporated
va
outlet
spring
Fig. 3.1
(a) The pond is kept at a depth of 2.0m. The density of water is 1000 kam
Calculate the water pressure on the valve.
A. 20 Pa
B.
20000 Pa
o 10000 Pa
D. 100 Pa​

I didnt understand it sorrryr

Explanation:

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

amplitude

hope this