An ideal gas expands isothermally performing 4.30 x 10³ of work in the process. Calculate (a) the change in internal energy of the gas, and (b) the heat absorbed during this expansion.​

The solution of the given query is explained below in the explanation portion.

Explanation:

Given value is:

Work,

⇒  

(a)

The change in the internal energy will be:

⇒  

Throughout the isothermal procedure, The temperature will be constant "ΔT = 0".

then,

⇒  

⇒  

(b)

As we know,

⇒  

On substituting the value, we get

⇒      

On adding W both sides, we get

⇒    

⇒    

On substituting the given value of "W", we get

⇒        

grav potential energy