Otion 17 A cyclist is moving with a speed of 18km/h on a plane road. He turns the bicycle on the cir
radius 3m. The coefficient of friction between the tyres and road is 0.1. Will he skid or not?​

SKID

Explanation:

In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

     N- W = 0

     N = W

X axis (radial)

        fr = m a

the acceleration in the curve is centripetal

         a =

the friction force has the expression

        fr = μ N

we substitute

       μ mg = m v²/r

       v =

we calculate

      v =

      v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

        v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID