Q7. A 2kg ball is released from a height of 20m. What is it velocity when its height has decreased to 5
m?​

Given,

Mass, m = 2kg

Height or distance, s = 20m

Initial velocity, u = 0m/s

Acceleration due to gravity, g = 10m/s (It is 9.8m/s but can be assumed 10m/s for simplifying calculations)

(Because the object is is just dropped)

Final velocity, v = ?

Solution

v^2 = u^2 + 2as (u^2 means u raised to power 2)

=> v^2 = 0^2 + 2*10*20

=> v^2 = 400

=> v = 20

Thus the velocity just before the body strikes the ground will be 20m/s.

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.