Adriver, traveling at 22.0 m/s, slows down her 2.00 x 103 kg car to stop for a red light. what work is done by the friction force against the wheels?

Some work will be done on friction between wheels and road but it is negligible compared to work done on friction on breaks. 

W = Ek = (m*v^2)/2 = 2000*22^2/2 = 1000*22^2 = 484KJ

Because car is not changing its potential energy, there is no work to be done on while changing it which means that all goes on changing kinetic energy (energy of motion)

Iwould say a is accurate

Molybdeum(mo)orruthenium (ru)actually, elements with similar chemical properties as technetium would bemn, re, and bh. this is because elements in the same group/family (column) have similar chemical properties. elements in the same period (row) have the same number of energy levels (or shells).