A3 kg mass moving to the right at 8 m/s collides with a 2 kg mass traveling left at a velocity of 6 m/s. After the collision, the 3 kg mass is
now traveling to the left with a velocity of 2 m/s. What is the velocity of
the 2 kg mass traveling to the right? (Hint: traveling in the left direction
should be represented with a negative velocity.)

The correct answer is  "c".  it is "c" because melting is an endothermic change, and endothermic get's energy from surroundings. 

Tons?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

The law of conservation of momentum will be the same no matter where you apply it.the equation will be  77.4 + m (mass of canister) *3.6