1/a-b +1/b-a =?
please help me​

1/a-b +1/b-a = (1/(a-b)) + (1/(b-a)) now by taking minus sign in common we get (1/(a-b)) + (1/(b-a)) (1/(a-b) + (1/-(-b+a)) = (1/(a-b)) + (1/-(a-b)) but as we know thatX/(-y) = -(X)/y %3D so we get (1/(a-b) + (1/-a-b)) = (1/(a-b) + (-1/(a-b)) %3D = (1/(a-b) -(1/(a-b) %3D now as denominator are same (1/(a-b)) -(1/(a-b)) = (1-1)/(a-b) 0/(a-b) nobut as we know that zero divided by anything except O is 96 % SO O/(a-b) = 0 hence (1/(a-b)) + (1/(b-a))= O

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