Remove the second lightbulb, and then design a parallel circuit using two lightbulbs that have the same resistance. How does the use of power in the parallel circuit compare to the
use of power in the simple circuit with one bulb?

Iwas going to ask that quesytion  sorry dude i dont  know : (    : /

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.