A wire carries a current of 4.2 A at what distance from the wire does the magnetic field have a magnitude of 1.3×10^ -5 t

the distance is 6.46 cm.

Explanation:

Given

current in the wire, I = 4.2 A

magnitude of the magnetic field, B = 1.3 x 10⁻⁵ T

The distance from the wire is determined by using Biot-Savart Law;

Where;

r is the distance from the wire where the magnetic field is experienced

Therefore, the distance is 6.46 cm.

it was given as a lesson and guide for prayer.

the answer is 12 as i may remember

: )