The mean orbital radius of the earth around the sun 1.5 × 108 km. Calculate the mass of the sun if G = 6.67 × 10-11 Nm2/kg -2?​

M = 1.994 × 10^(30) kg

Explanation:

We are given;

Orbital radius; r = 1.5 × 10^(8) km = 1.5 × 10^(11) m

Gravitational constant; G = 6.67 × 10^(-11) N.m²/kg²

If the orbit is circular, the it means the gravitational force is equal to the centripetal force.

Thus; F_g = F_c

GMm/r² = mv²/r

Simplifying gives;

GM/r = v²

M = v²r/G

Now, v is the speed of the earth around the sun and from online sources it has a value of around 29.78 km/s = 29780 m/s

Thus;

M = (29780^(2) × 1.5 × 10^(11))/6.67 × 10^(-11)

M = 1.994 × 10^(30) kg

a

explanation:

because they are cartillidge

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach