a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel during 30 seconds of rotation?​

50π m ≈ 157 m

Explanation:

100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s

d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.