A snowflake (1.5 x 10-9 kg) falls to Earth's surface under gravity (9.8 m/s2). What is the force of the snowflake?

1.47×10¯⁸ N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1.5×10¯⁹ Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

The force of the snowflake can be obtained by using the following formula:

F = mg

Where:

F => is the force

m => is the mass

g => is the acceleration due to gravity

F = mg

F = 1.5×10¯⁹ × 9.8

F = 1.47×10¯⁸ N

Thus the force of the snowflake is 1.47×10¯⁸ N

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever