A wire along the z axis carries a current of 4.9 A in the +Z direction. Find magnitude of the force exerted on a 3.3 cm long length of this wire by a uniform magnetic field pointing in the -x direction having a magnitude 0.43 T

   F = - 6.95 10⁻² j^  N

Explanation:

The force on a wire carrying current through a magnetic field is

         F = i L x B

The bold letters indicate vectors, as the wire is in the positive Z axis and the magnetic field in the negative x axis, the force must be in the negative y axis

the force module

            F = i LB

that there is 90º between the two vectors and the sin 90 = 1

let's calculate

            F = 4.9  3.3 10⁻² 0.43

            F = 6.95 10⁻² N

the force vector is

           F = - 6.95 10⁻² j^  N

mistakes are ok