1. A 455 g mass, hanging at rest on a spring, stretches the spring 22.4 cm beyond its relaxed position. What is the spring constant of that spring?

19.9 N/m

Explanation:

From the question,

Applying Hook's law

F = Ke Equation 1

Where F = Force on the spring, k = spring constant, e = extension

But the force on the spring is the weight of the mass

Therefore,

mg = ke Equation 2

Where m = mass. g = acceleration due to gravity

make e the subject of the equation

e = mg/e Equation 3

Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,

Constant: g = 9.8 m/s²

Substitute these values into equation 3

e = (0.455×9.8)/0.224

e = 19.9 N/m

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

this is poiselle's equation from fluid mechanic in physics. mech eng