Physics, 02.04.2021 06:20 ayoismeisalex

PLEASE HELP - In running a ballistics test at the police department, Officer Rios fires a 6.1g bullet at 350 m/s into a container that stops it in 0.32 min. What average force stops the bullet?

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Answer from: thegreentnt5025

–0.11 N.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 6.1 g

Initial velocity (u) = 350 m/s

Time (t) = 0.32 mins

Final velocity (v) = 0 m/s

Force (F) =?

Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

0.32 mins = 0.32 × 60 = 19.2 s

Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:

Initial velocity (u) = 350 m/s

Time (t) = 19.2 s

Final velocity (v) = 0 m/s

v = u + at

0 = 350 + (a × 19.2)

0 = 350 + 19.2a

Collect like terms

0 – 350 = 19.2a

–350 = 19.2a

Divide both side by 19.2

a = –350 / 19.2

a = –18.23 m/s²

Next, we shall convert 6.1 g to Kg.

1000 g = 1 Kg

Therefore,

6.1 g = 6.1 g × 1 Kg / 1000 g

6.1 g = 0.0061 Kg

Finally, we shall determine the force. This can be obtained as follow:

Mass (m) = 0.0061 Kg

Acceleration (a) = –18.23 m/s²

Force (F) =?

F = ma

F = 0.0061 × –18.23

F = –0.11 N

NOTE: The negative sign indicates that the force is in opposite direction.

Answer from: sadsociety41

–0.11 N.

Explanation:

Hope this helps

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Answer from: Quest

Scissors and a seesaw both cut things that’s the only comparison

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