Two people are competing in a tubing competition. They push a 132 kg inner tube. If the combined push of the team is 450 N and the inner tube also experiences a friction force of 35 N, what is the acceleration of the inner tube? (F = ma) The inner tube's acceleration is 3.18\frac{m}{s^2}

The inner tube's acceleration is 9.08\frac{m}{s^2}

The inner tube's acceleration is 3.6\frac{m}{s^2}

The inner tube's acceleration is 9.8\frac{m}{s^2}

The inner tube's acceleration is 3.14\frac{m}{s^2}

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