Acyclist maintains a constant velocity of
4 m/s headed away from point a. at some
initial time, the cyclist is 253m from point a.
what will be his displacement from his
starting position after 64 s?
answer in units of m

what will be his position from point a after
that time?
answer in units of m

The answer is 509 m.

Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).

Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s

4 = d2/64
d2 = 64 * 4 = 256 m

Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m

It is d, all the other ones say incorrect answer .