Afirefighter mounts the nozzle of his fire hose a distance 36.9 m away from the edge of a burning building so that it sprays from ground level at a 45° angle above the horizontal. after quenching a hotspot at a height of 8.85 m, the firefighter adjusts the nozzle diameter so that the water hits the building at a height of 17.9 m. by what factor was the nozzle diameter changed? assume that the diameter of the hose stays the same, and treat the water as an ideal fluid.

diameter is decreased by factor 0.91

Explanation:

As we know by the equation of trajectory

here as per first given situation we know that

x = 36.9 m

y = 8.85 m

now from above equation we have

now similarly after nozzle is adjusted we have

y = 17.9 m

x = 36.9 m

now again from equation we have

Now by equation of continuity we can find the change in diameter

as we know that

now we have

so we have

so diameter is decreased by factor of 0.91

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!