What is the current in a 160 V circuit if the resistance is 2 ohms?

Question: What is the current in a 160V circuit if the resistance is 2Ω?

Voltage ( V ) = 160V

Resistance ( R ) = 2Ω

Current ( I ) = ?

By Ohms law

⇒ V = IR

⇒ 160 = I × 2

⇒ I = 160 / 2 = 80A

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Question: What is the current in a 160V circuit if the resistance is 20Ω?

Voltage ( V ) = 160V

Resistance ( R ) = 20Ω

Current ( I ) = ?

By Ohms law

⇒ V = IR

⇒ 160 = I × 20

⇒ I = 160 / 20 = 8A

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Question: What is the current in a 160V circuit if the resistance is 10Ω?

Voltage ( V ) = 160V

Resistance ( R ) = 10Ω

Current ( I ) = ?

By Ohms law

⇒ V = IR

⇒ 160 = I × 10

⇒ I = 160 / 10 = 16A

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Question: Based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? Increases?

From ohms law

⇒ I = V / R

If we take Voltage as proportionality constant

⇒ I ∝ 1 / R

So, we can conclude that current is inversely proportional to resistance.

From 2, 3, 4 questions we can conclude that,

If resistance increases, current decreases and when resistance decreases, current increases.

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Question: What voltage is required to move 6A through 5Ω?

Resistance ( R ) = 5Ω

Current ( I ) = 6A

Voltage ( V ) = ?

By Ohms law

⇒ V = IR

⇒ V = 6 × 5

⇒ V = 30V

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Question: What voltage is required to move 6A through 10Ω?

Resistance ( R ) = 10Ω

Current ( I ) = 6A

Voltage ( V ) = ?

By Ohms law

⇒ V = IR

⇒ V = 6 × 10

⇒ V = 60V

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Question:What voltage is required to move 6A through 20Ω?

Resistance ( R ) = 20Ω

Current ( I ) = 6A

Voltage ( V ) = ?

By Ohms law

⇒ V = IR

⇒ V = 6 × 20

⇒ V = 120V

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6/12=1/2

step-by-step explanation:

yup its correct its: c) b b