Ablock is sent up a frictionless ramp along which an x axis extends upward. the figure below gives the kinetic energy of the block as a function of position x; the scale of the figure's vertical axis is set by ks = 46.0 j. if the block's initial speed is 4.50 m/s, what is the normal force on the block?

Kinetic energy =1/2 mv^2 

m=2ke/v^2 

m=2(34)/3.6^2 

m=5.24 

force normal = mg 
=5.24 x 9.8 
force normal = 51.4N

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Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

The sample with the lowest specific heat capacity will have the greatest temperature increase. in this case, it would be platinum.