What is the kinetic energy of a 6 kg and 2 m long thin rod that rotates with angular velocity of 10 rad/s about an axis that passes at its edge?
A. 2400 J
B. 1200 J
C. 200 J
D. 800J​

1200 J

Explanation:

From the question

K.E = 1/2mv² Equation 1

Where K.E = Kinetic Energy, m = mass of the rod, v = velocity of the rod

But

V = ωr Equation 2

Where   ω = angular velocity of the rod, r = radius of the rod.

Substitute equation 2 into equation 1

K.E = 1/2m(ωr)² Equation 3

Given: m = 60 kg,  ω = 10 rad/s, r = 2 m

Substitute these values into equation  3

K.E = 1/2(6)(10×2)²

K.E = 3×(20)²

K.E = 3×400

K.E = 1200 J

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