Four charges of equal charge+q are placed at the corners of a rectangle of sides a and b. What is the potential at the center of the rectangle if q = 2.0 uc, a = 3.0 cm, and b = 4.0cm?​

V = 32.2 10³ V

Explanation:

The electric potential is a scalar quantity given by the expression

          V = h ∑  

Let's find the distance from each corner to the center of the square, using Pythagoras' theorem

           r =

indicate that all charges have the same magnitude and the casticista from each scheme to the center is r

           V = k q ()

let's calculate

            r = ½ Ra 2² + 4²

            r = 2,236 m

           V = 9 10⁹ 2 10⁻⁶  4 / 2,236

           V = 32.2 10³ V

be subject to a force andchange its motion

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.