A pelican flying along a horizontal path drops a fish from a height of 7.0 m. The fish travels 8.0 m horizontally before
it hits the water below. What is the pelican's speed?

time for fish to fall 5.4 m = √2d/g = √(2)(5.4)/9.81 = √1.100917 = 1.0492 s

pelican's initial speed = horizontal fish speed = 8.0/1.0492 = 7.6 m/s ANS a)

time for fish to fall 2.7 m = √2d/g = √0.55046 = 0.7419 s

fish travels a distance = speed x time =  (7.6)(0.7419) = 5.6 m ANS b)

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)