a body of mass 12kg hangs from a fixed point by a light inextensible string. A horizontal force is applied to the body such that the body is in equilibrium when the string Is inclined at 35⁰ to the vertical. Find, correct to 1 decimal place the horizontal force and the tension in the string. Take g=9.8m/s²​

need to see circuit to get time constant

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

k2s for potassium sulphide

the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.