Physics, 21.08.2019 23:00 melany682296

Is a mirrors surface transparent translucent or opaque how do you know.

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Answer from: josh200508

There are actually two different kinds of mirrors, and the answer is different
for each one.

-- Plain old everyday hand mirror, vanity mirror, bathroom mirror, makeup
mirror, etc.

Opaque, reflecting silver coating is on the back of the glass.
Light from your tongue or your teeth flows to the front surface of the glass,
through the glass, out of the back surface of the glass, bounces off of the silver
coating on the back, reverses its direction, enters the back surface of the glass,
comes back through the glass again, leaves the front of the glass, goes into your
eyes, and you can see your teeth or your tongue.

Both surfaces of the glass, as well as the glass in between the surfaces, are
transparent. The silver coating on the back is opaque. I know that, because
when I look at the back of a mirror, I can't see any light coming through it.
The coating on the back is also reflective ... a big part of the reason why
a mirror works.

-- Expensive mirrors used by astronomers and eye-doctors.
Known as "first surface" mirrors.

Opaque, reflecting silver coating is on the front of the glass.
Light from your tongue or your teeth flows toward the front surface of the glass,
but never actually gets there. It bounces off of the silver coating on the front of
the glass, reverses its direction, goes into your eyes, and you can see your teeth
or your tongue.

The glass is transparent, but that doesn't matter, because the light never reaches
the glass. It only goes as far as the opaque silver coating on the front, and is
reflected from there.

Answer from: Quest

By dividing you can find the answer

Answer from: Quest

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6 $\frac{m}{s^{2} }$

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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