A body of mass 250g is release d from the top of a building. If the body hits the ground with a velocity of 4m/s, calculate the height of the building (g = 10 m/s squared)​

the height of the building is 0.8 m.

Explanation:

Given;

mass of the object, m = 250 g = 0.25 kg

final velocity of the object, v = 4 m/s

let the height of the building = h

Apply the principle of conservation of energy to determine the height of the building;

¹/₂mv² = mgh

¹/₂v² = gh

Therefore, the height of the building is 0.8 m.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.