A student pulls down with a force of 40 N on a rope that winds around a pulley of radius 5 cm. find the torque?

2N

Explanation:

Given that a student pulls down with a force of 40 N on a rope that winds around a pulley of radius 5 cm. find the torque?

Solution

Using the formula

Torque = Force × radius

I.e

Torque = F r

Where

F = 40N

r = 5 cm = 5/100 = 0.05m

Substitute all the parameters into the formula

Torque = 40 × 0.05

Torque = 2 N

Therefore, the torque on this scenario is 2 N

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz