A ray of light has a wavelength 433 nm in water (n = 1.33). What
is its wavelength in a vacuum?
(Remember, the wavelength is longer in
a vacuum.)
(Unit = nm)

The wavelength of the light in a vacuum is 575.89 nm

Explanation:

The given parameter in the are;

The wavelength of the ray of light in water, λ₁ = 433 nm

The refractive index of water, n₁ = 1.33

The relationship between wavelength, λ, and refractive index, 'n', is presented as follows;

λ₁·n₁ = λ₂·n₂

Where;

λ₁ and λ₂ are the wavelength of the wave within  the two mediums

n₁ and n₂ are the respective refractive indices of the mediums

The refractive index of vacuum, n₂ = 1

Let λ₂ represent the wavelength of light in vacuum

Therefore, we have;

1.33 × 433 nm = 1 × λ₂

∴ λ₂ = 1.33 × 433 nm/1 = 575.89 nm

Therefore, the wavelength in a vacuum, λ₂ = 575.89 nm

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards