A hose, of radius 0.018 m, is connected to a water faucet. The water pressure at the point where the hose connects to the faucet is 150,000 Pa. The other end of the hose is connected to an outlet of radius 0.011 m, where the water comes out. The total length of the hose and outlet is 15 m. (a) An experiment shows that the water exists the outlet with a speed 5.2 m/s. What is the flow rate through the hose?
(b) What is the maximum height that the end of the outlet can he held above the faucet, and water still comes out?
(c) Suppose there is a small hole in the hose. How does that affect the speed at which the water comes out? Explain.

Explain each step!

A hose, of radius 0.018 m, is connected to a water faucet. The water pressure at the point where the hose connects to the faucet is 150,000 Pa. The other end of the hose is connected to an outlet of radius 0.011 m, where the water comes out. The total length of the hose and outlet is 15 m.

(a) An experiment shows that the water exists the outlet with a speed 5.2 m/s. What is the flow rate through the hose?

(b) What is the maximum height that the end of the outlet can he held above the faucet, and water still comes out?

(c) Suppose there is a small hole in the hose. How does that affect the speed at which the water comes out? Explain.

Explain each step!

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to all who liked my answers

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to all who liked my answers

pl flw

can anyone pls flw me who aren't flwingthankew 人(◕ᴗ◕✿)❤️

to all who liked my answers

pl flw

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Just taking points

Explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂