A 1500 kg car is being lifted by a hydraulic jack attached to a flat plate. Underneath the plate is a pipe with radius of 24 cm at the top and 2cm at the bottom. To generate an upward acceleration for the car of 1.0 m/s2, how much force must be applied to the small end of the pipe? The answer is NOT 102 N btw

The force that must be exerted at the other end is 102.08 N/m₂

Explanation:

Using Pascal's formula; P₁ = P₂

P₁ = F₁/A₁ = m*g/(πr²)

m = 1500 kg; g = 9.8 m/s², r = 24 cm = 0.24 m

P₁ = (1500 * 9.8)/(22/7 * 0.24 * 0.24)

P₁ = 81235 N/m²

P₂ = F₂/A₂

A₂ = πr² where π = 22/7; r = 2.00 cm = 0.02m

A₂ = 22/7 * 0.02 * 0.02 = 0.00126 m²

P₂  = F₂ / 0.00126 m₂

substituting in the formula  P₁ = P₂

81235 N/m² =  F₂ / 0.00126 m²

F₂ = 81235 N/m² * 0.00126 m²

F₂ = 102.08 N/m₂

Explanation:

Why does water stop flowing out of the top hole even before the water level falls ... Calculate pressure on the bottom of the pool due to the water. 3. ... 2. If the ratio of A2 to A1 was 100, what force would be required to lift a 10000 N car? ... A cylinder with a radius of 11 cm and a height of 3.4 cm has a mass of 10.0 kg. a.

Explanation: