A person drives a car around a circular road with a constant speed of 20 m/s. The radius of the circular road is twenty-five meters. What is the acceleration of the car?
o 20 m/s2
O 16 m/s2
O 10 m/s2
O 8 m/s2

16 m/s^2

Explanation:

acceleration tangential = (v^2)/r

a=400/25

a=16 m/s^2

Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:

angular acceleration=acceleration tangential/r

angular acc.=16/25

angular acc.=0.64 rad/s^2

terd muffin is the correct answer

higher potential

explanation:

because it is in a high speed so it must move into a of high potential