A helicopter moves with a constant velocity v, - 4 m/s from point A to point B during a time interval tas = 10 s. It then accelerates from point B to point C with constant acceleration az =
2m/s2 for a time interval tac = 20 s. The average velocity of this helicopter for the whole trip is
equal to:
A
tas-10
tec-20 s
Q2 = 2m/s2
Di=4 m/s​

i think they are all correct

explanation:

they seem good

0.19 m/s and 0.45 m/s

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