An 5kg object is released from rest near the surface of a planet. The vertical position of the object as a function of time is shown in the graph. All frictional forces are considered to be negligible. What is the closest approximation of the weight of the object. a) 300N
b) 30N
c) 5N
d) 150N

The correct option is b: 30 N.

Explanation:

First, we need to find the acceleration due to gravity (a):

  (1)

Where:

: is the final vertical position (obtained from the graph)

: is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → = 5 s

y₀ = 300 m → = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

Finally, the weight of the object is:

Therefore, the correct option is b: 30 N.

I hope it helps you!                                                                                                            

real, smaller and upside-down.   so the answer should be b.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day