PLEASE HELP PHYSICS Wiley coyote pushes a 5kg boulder from an initial height of 10m, the boulder rolls down the hill, across the road, and up the hill on the left. The rock is able to reach a height of 17 m before rolling back down. How fast did Wiley have to push the rock to make this happen?

  v = 11.7 m / s

Explanation:

For this exercise we can use the conservation of energy

starting point. Where you drop the stone

          Em₀ = K + U = ½ m v² + m g h₁

final point. Point where the stone arrives

          Em_f = U = mgh₂

We are assuming that there is no friction, so the energy is conserved

          Em₀ = Em_f

          ½ m v² + m g h₁ = m g h₂

         v² = 2g (h₂-h₁)

let's calculate

         v² = 2 9.8 (17 - 10)

         v = √137.2

         v = 11.7 m / s

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2