A 755 N diver drops from a 10.0 m board that is above the water's surface. A) Find the Diver's speed 5.00m above the water.
B) Then, find the diver's speed just before striking.

F = 755N, and h = 10.0 m and a = 9.8 m/s^2 and m =? and v = ?To find the mass use F = ma 755 = (m)(9.8)  and m = .77 kg then use the formula KE + PE = PE2 + KE2 which is 1/2mv2 + mgh = mgh(2) + 1/2mv2 (2) to solve for the velocity. v1 = 0 and h1 = 10 and v2 = ? and h2 = 0 (1/2)(.77)(0^2) + (.77)(9.8.)(10) = (1/2)(.77)(V2^2) + (.77)(9.8)(0)v=14 m/s

Explanation:

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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