A car of weight 11 000 N moves with constant velocity along a horizontal road. A driving force of 5000 N acts on the car. What is the force opposing the motion of the car?

f = 5000 N

Explanation:

Given that,

The weight of a car = 11000 N

Driving force on the car = 5000 N

We need to find the force opposing the motion of the car. The net force on th car is given by :

F-f = ma

As it moves with constant velocity, a = 0

i.e.

F - f = 0

F = f

f = 5000 N

Hence, the opposing force is 5000 N.

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snell's law

refractve index = sin incidence / sin refraction