A student lifts their 5 kg backpack 2 meters off the floor. How much work does the student do on the backpack? 5/2= 2.5 J
5 x 2 = 10 W
5/2 = 2.5 W
5 x 2 = 10 J

Part f - example: finding two forces (part i) two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. the block in (figure 1) has a mass m=10kg and is being pulled by a force f on a table with coefficient of static friction îľs=0.3. four forces act on it: the applied force f (directed î¸=30â above the horizontal). the force of gravity fg=mg (directly down, where g=9.8m/s2). the normal force n (directly up). the force of static friction fs (directly left, opposing any potential motion). if we want to find the size of the force necessary to just barely overcome static friction (in which case fs=îľsn), we use the condition that the sum of the forces in both directions must be 0. using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: fcosî¸â’îľsn=0 fsinî¸+nâ’mg=0 in order to find the magnitude of force f, we have to solve a system of two equations with both f and the normal force n unknown. use the methods we have learned to find an expression for f in terms of m, g, î¸, and îľs (no n).

For which pair of objects would adding the same a

Auniform brick of length 25 m is placed overthe edge of a horizontal surface with a maximum overhang of 12.5 m attained withouttipping. now two identical uniform bricks of length25 m are stacked over the edge of a horizontalsurface. what maximum overhang is possible forthe two bricks (without tipping)? answer in units of m.