Physics, 18.03.2021 01:00 cherokeesiouxw72

Can someone please help me fill in the last three please it’s physics how to find mass

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electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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The anwser is: wave a has a greater pitch and frequency.

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Ray 2 should cross through the focal point on the right side of the lens

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This is actually a calculus question. so, basically, this is a related rates question where you are given 1 quantity and you have to find the other. we'll define some variables first.x = 9 ftdx/dt = 7 ft/secl = 15 ftsince you want to find the area, you have to find a formula for it. which is: $a = \frac{1}{2}x*h$ we know the base (x), but we don't know the height (h). we can figure it out by solving for it. we have to form an equation which we can figure out height from given the information we have. this equation is: $x^2+h^2=l^2$ plug in known values: $9^2+h^2=15^2$ solve for h: $h^2 = 15^2-9^2$ $h^2=144$ $h = \sqrt{144}=12$ now, let's solve for the rate at which h is changing. we can do so by differentiating the pythagorean theorem (above). let's do that: $x^2+h^2=15$ $2x \frac{dx}{dt}+2h \frac{dh}{dt}=0$ $\frac{dh}{dt} = \frac{-2x \frac{dx}{dt} }{2h}$ $\frac{dh}{dt} = \frac{-x \frac{dx}{dt} }{h}$ plug in values: $\frac{dh}{dt} = \frac{-9*7}{12} = \frac{-63}{12} = \frac{-21}{4}$ now we have all the given information to do this problem. so, to figure out the rate of change of area, we can differentiate (with respect to time) the earlier equation: $\frac{d}{dt}(a) = \frac{d}{dt} (\frac{1}{2}x*h)$ which is equal to: $\frac{da}{dt}= \frac{1}{2}( \frac{dx}{dt}h+x \frac{dh}{dt})$ plug in known values: $\frac{da}{dt} = \frac{1}{2}(7*12+9* \frac{-21}{4} ) = \frac{1}{2}(84- \frac{189}{4} )$ $\frac{1}{2}( \frac{147}{4}) = \frac{147}{8}$ so, the area of the triangle is changing at approximately 18.375ft²/sechope this all makes sense. if it doesn't, either contact me, or watch khan academy - he explains it real well. special credit to turtaniumx and quietself for letting me know of the error, and fix it!

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Can someone please help me fill in the last three please it’s physics how to find mass
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