You pull a 55kg wooden box with a rope that makes a 24 degree angle with the horizontal at a constant speed. The acceleration due to gravity on the box is 9.8 m/s2. You pull the crate a distance of 2.2 m. How much work was done?

Workdone: F x S x Cos(x)

F:mg

m:55kg g: 9.8?m/s²

F: 55 x 9.8

F:539N

Workdone: FS x Sin(x)

F:539N

S: 2.2m

x:24°

539 x 2.2 x Sin(24)

1185.8 x 0.4067

=482.3083J

=482.31J

Explanation:

Sin(x) is used instead of Cos(x) because the 24° angle is to the horizontal.

because growing process had stoped after 4-5 year

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft