Un hombre camina 400m hacia el oeste luego 200m hacia el norte. Determina la magnitud y la dirección del desplazamiento resultante

d = 447.21 m,   θ = 153.4º

Explanation:

Let's use the Pythagoras network theorem to find the magnitude of the displacement

          d =

          d =

          d = 447.21 m

To encode the direction, let's use trigonometry, we take the East and North directions as positive.

          tan θ’= y / x

          θ'= tan⁻¹ y / x

          θ'= tan⁻¹ (200/400)

          θ ’= 26.6º

This angle is in the second quadrant, so measured from the positive side of the x-axis (East direction)

          θ = 180 - θ'

          θ = 180 -26.6

          θ = 153.4º

attach the statements so i can answer : )

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles