A body of mass 30 kg moving north a velocity of 0.5 ms-1 subjected of 15 N North for 2.7 s. No need to explain just give me the answer I’m in a test thanks

Question: a body of mass 30 kg moving north a velocity of 0.5 ms-1 subjected of 15 N North for 2.7 s.  Calculate the final velocity of the body.

14 m/s

Explanation:

From the question,

F = ma Equation 1

make a the subject of the equation

a = F/m Equation 2

Given: F = 15 N, m = 30 kg.

Substitute these values into equation 2

a = 15/3

a = 5 m/s².

Using,

a = (v-u)/t Equation 3

Where v = final velocity, u = initial velocity, t = time.

Given: u = 0.5 m/s, t = 2.7 s and a = 5 m/s²

Substitute these values into equation 3

5 = (v-0.5)/2.7

(v-0.5) = 5×2.7

v-0.5 = 13.5

v = 13.5+0.5

v = 14 m/s

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6