what is the displacement and direction of resultant vector if runs at 55.0m at an angle at N27W and then runs 23.0m at an an angle of S5W from new location

im guessing the west of station b

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

higher potential

explanation:

because it is in a high speed so it must move into a of high potential