the magnetic flux density of a given conductor is 3.6T. Given that the conductor generates 12.9N and has a length of 10cm, calculate the current being carried

i = 5.28 A

Explanation:

The magnetic force is given by the expression

          F = i l x B

the bold letters indicate vectors, let's write the modulus of that expression, where the direction between the conductor and the magnetic field is 90º, therefore the sine 90 = 1

           F = i l B

           i = F / l B

let's reduce the length to the SI system

           l = 10 cm (1m / 100 cm) = 0.10 m

let's calculate

           i = 12.9 / 0.1 3.6

           i = 5.28 A

the answer is a. at the equator