An aeroplane makes in emergency landing without landing gear. if the aeroplane touches down with a horizontal speed of 60.0ms^-1 and the coefficient of friction for aluminium on asphalt is μ = 0.500, how far will the aeroplane slide before coming to rest? you may assume that acceleration due to gravity is 10.0ms^-2 and that air resistance is negligible.

Below is the solution;

Fp = Mg*sin 0 = 0. 
Fn = Mg*Cos 0 = Mg = Normal force. 
Fk = u*Fn = 0.50*Mg. 

Fp-Fk = M*a. 
0-0.5Mg = M*a, Divide by Mg: 
-0.5 = a/g = a/-10, a = 5 m/s^2. 

V^2 = 60^2 - 10d. 
0 = 3600 -10d, d = 360 m.

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Iassume the answer is 75 feet. inwards to outwards rather than outwards to inwards. probably be 75.hachures are stokes drawn in direction of the steepest slope. a series of short parallel lines drawn on a map to indicate topographic relief. it is actually called hachures on contour lines. the small marks in the center of the feature are called hachures.observe the picture attached