A ball is tossed vertically upward with a speed of 18 m/s from the ground. (a) How long does it take the ball to reach the top of its trajectory?

(b) What was the height of the ball at the top of its trajectory?

he . if i may ask what i your question exactly?

explanation:

massxgravity x heght=weightxheight= pe

4900=490xh

h=10

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.