A ball is thrown 6m above the ground. Its total energy at that point is 12 J. What is the total energy of the ball at a halfway point of motion

5.99 J

Explanation:

A ball is thrown 6m above the ground.

Its total energy at that point is 12 J.

The energy of the ball is given by :

E = mgh

Where

m is the mass of the ball

Let E' is the total energy of the ball at a halfway point of motion. h' = 3 m

So,

So, the required energy is 5.99 J.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft