A ball (A) of mass 1.4kg is moving with a speed of 3.7m/s collides with a 0.55kg ball (B) which is at rest. If Ball A is going 2.3m/s after the collision, what will the velocity of Ball B be after the collision?

5.94m/s

Explanation:

Using the law of conservation of momentum;

mAuA+ mBuB = mAvA+mBvB

Substitute the given values

1.4(3.7) + 0.55(0) = 1.4(2.3) + 0.55vB

5.18 + 0 = 3.22 + 0.55vB

5.18 - 3.22 = 0.55vB

1.96 = 0.33vB

vB = 1.96/0.33

vB = 5.94m/s

Hence the velocity of Ball B be after the collision is 5.94m/s

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr